If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, what type of circuit is it?

If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, what type of circuit is it?

• A. Only series circuit
• B. Series-parallel circuit
• C. Only parallel circuit
• D. Single resistor circuit

Answer: (B)

A circuit that consists of multiple resistors can be configured in different ways, and understanding the configuration is crucial for determining the total resistance. In this scenario, five 50-ohm resistors are mentioned, and the total resistance of the circuit is given as 10 ohms. When resistors are connected in series, their resistances add up directly. If all five resistors were connected in series, the total resistance would be the sum of all the resistors: 50 ohms + 50 ohms + 50 ohms + 50 ohms + 50 ohms, which equals 250 ohms. This scenario does not match the total resistance of 10 ohms. On the other hand, when resistors are connected in parallel, the total resistance can be calculated using the formula: 1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn. In this case, if all five 50-ohm resistors were connected in parallel, the calculation would be: 1/R_total = 1/50 + 1/50 + 1/50 + 1/50 + 1/50 1/R_total = 5/

A circuit that consists of multiple resistors can be configured in different ways, and understanding the configuration is crucial for determining the total resistance.

In this scenario, five 50-ohm resistors are mentioned, and the total resistance of the circuit is given as 10 ohms. When resistors are connected in series, their resistances add up directly. If all five resistors were connected in series, the total resistance would be the sum of all the resistors: 50 ohms + 50 ohms + 50 ohms + 50 ohms + 50 ohms, which equals 250 ohms. This scenario does not match the total resistance of 10 ohms.

On the other hand, when resistors are connected in parallel, the total resistance can be calculated using the formula:

1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn.

In this case, if all five 50-ohm resistors were connected in parallel, the calculation would be:

1/R_total = 1/50 + 1/50 + 1/50 + 1/50 + 1/50

1/R_total = 5/